Resumen
Let k be a fixed algebraic closure of and k(t)ac a fixed algebraic closure of k(t). Let Sk[t]\ {0} be a multiplicative set. Let A=S-1(k[t]) and [image omitted] be the integral closure of A in k(t)ac. We use elliptic curves to develop a necessary condition on S for [image omitted] to be a Bezout domain. We give some examples of S which fail to satisfy this condition. As a consequence, we eliminate some candidates for a good Rumely domain of characteristic 0 with algebraic subring k.
| Idioma original | Inglés |
|---|---|
| Páginas (desde-hasta) | 4492-4499 |
| Número de páginas | 8 |
| Publicación | Communications in Algebra |
| Volumen | 36 |
| N.º | 12 |
| DOI | |
| Estado | Publicada - dic 2008 |
Huella
Profundice en los temas de investigación de 'Bezout domains and elliptic curves'. En conjunto forman una huella única.Citar esto
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