Abstract
Let k be a fixed algebraic closure of and k(t)ac a fixed algebraic closure of k(t). Let Sk[t]\ {0} be a multiplicative set. Let A=S-1(k[t]) and [image omitted] be the integral closure of A in k(t)ac. We use elliptic curves to develop a necessary condition on S for [image omitted] to be a Bezout domain. We give some examples of S which fail to satisfy this condition. As a consequence, we eliminate some candidates for a good Rumely domain of characteristic 0 with algebraic subring k.
| Original language | English |
|---|---|
| Pages (from-to) | 4492-4499 |
| Number of pages | 8 |
| Journal | Communications in Algebra |
| Volume | 36 |
| Issue number | 12 |
| DOIs | |
| Publication status | Published - Dec 2008 |
Keywords
- Bezout domain
- Elliptic curve
- Good Rumely domain
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