Abstract
We give an algebraic proof of the Birman-Bers theorem - an algebraic result whose previous proofs used topology or analysis, and which says that a certain subgroup of finite index in the (algebraic) mapping class group of an oriented punctured surface is isomorphic to a certain group of automorphisms. The index 2 case gives rise to an automorphism of the group consisting of those automorphisms of a free group that stabilize the normal subgroup generated by an oriented-surface relator, and we analyze this curious automorphism. © 1997 Academic Press.
Original language | English |
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Pages (from-to) | 58-89 |
Journal | Journal of Algebra |
Volume | 189 |
DOIs | |
Publication status | Published - 1 Mar 1997 |